(X+1)(x+2)=x^2+5x

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Solution for (X+1)(x+2)=x^2+5x equation: 



(X+1)(X+2)=X^2+5X

We move all terms to the left:

(X+1)(X+2)-(X^2+5X)=0

We get rid of parentheses

-X^2+(X+1)(X+2)-5X=0

We multiply parentheses ..

-X^2+(+X^2+2X+X+2)-5X=0

We add all the numbers together, and all the variables

-1X^2+(+X^2+2X+X+2)-5X=0

We get rid of parentheses

-1X^2+X^2+2X+X-5X+2=0

We add all the numbers together, and all the variables

-2X+2=0

We move all terms containing X to the left, all other terms to the right

-2X=-2

X=-2/-2

X=1

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